On Mon, 11 Mar 1996 11:25:28 -0500 you wrote:
SJ>...Brian...wrote (quoting Yockey):
>[...]
>BH>...For example, it is often said
>that the total possible number of proteins of 100 amino acids is 20^100 =
>1.26 x 10^130 ...
SJ>I thought that 20^100 was simply 10^130, eg.
>
>Log10 20 = 1.301029995664
>
> = 10^1.301029995664 (by Windows Calculator)
>
>therefore:
>
>20^100 = (10^1.301029995664)^100
>
> = 10^(1.301029995664*100)
>
> = 10^130.1029995664
BH>10^130.1029995664 = 10^.1029995664 x 10^130
>
> i.e. 10^(a+b) = 10^a x 10^b
>
>Now, 10^.1029995664 =~ 1.2676506
>
>so 10^130.1029995664 = 1.2676506 x 10^130
>
>Looks like Yockey rounded off incorrectly ;-).
Thanks. Also thanks to Art and Jim Hopper who wrote:
AC>But 10^130.1029995664 = 10^130 * 10^.1029995664
> = 10^130 * 1.26
JH>10^130.10299= 10^.10299*10^130 (x^a * x^b=x^(a+b)
> = 1.267x 10^130
I know 10^.1029995664 = 10^1.2675 by my calculator, but
why does it. ie. 10^1029 would be 1 followed by 1029 zeros,
but why should 10^.1029995664 = 1 followed by 1.2676506
zeros?
>I think a shorter route to the exponent of 10 is
>
>log[20^100] = 100log[20] = 130.1029995664
OK. Thanks. My maths is incredibly rusty.
God bless.
Steve
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