To the forum:
With reference to my email of 20 April, I made the following statement:
"Remarkably, when applied repeatedly to any multiple of 3 (expressed as
a denary object), the foregoing transform reduces ultimately to 153 - a
triangular number!"
Apparently, I have not made myself clear here. The 'transform' I refer
to converts a given number to the sum of the cubes of its digits. As an
example of my claim, consider 5961102378 - a multiple of 3. The repeated
application of the transform generates the following sequence:
5961102378 => 1962 => 954 => 918 => 1242 => 81 => 513 => 153
As another example, consider 3 itself:
3 => 27 => 351 => 153
Please note also that there is one multiple of 3 to which the claim does
not apply, viz 3 x 0 = 0!
Sincerely,
Vernon
http://homepage.virgin.net/vernon.jenkins/sixes.htm
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