>Brian
>
>On Mon, 26 Feb 1996 14:45:05 -0500 you wrote (quoting Yockey):
>
>[...]
>
>BH>...For example, it is often said
>>that the total possible number of proteins of 100 amino acids is 20^100 =
>>1.26 x 10^130 ...
>
>I thought that 20^100 was simply 10^130, eg.
>
>Log10 20 = 1.301029995664
>
> = 10^1.301029995664 (by Windows Calculator)
>
>therefore:
>
>20^100 = (10^1.301029995664)^100
>
> = 10^(1.301029995664*100)
>
> = 10^130.1029995664
>
10^130.1029995664 = 10^.1029995664 x 10^130
i.e. 10^(a+b) = 10^a x 10^b
Now, 10^.1029995664 =~ 1.2676506
so 10^130.1029995664 = 1.2676506 x 10^130
Looks like Yockey rounded off incorrectly ;-).
I think a shorter route to the exponent of 10 is
log[20^100] = 100log[20] = 130.1029995664
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Brian Harper |
Associate Professor | "It is not certain that all is uncertain,
Applied Mechanics | to the glory of skepticism" -- Pascal
Ohio State University |
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